Task 1999

I read the article Useful tickets and remembered the distant 1999, when I found a rather entertaining puzzle somewhere in a magazine. Immediately make a reservation that the condition is similar to the above article, but there are nuances. Its meaning in the following:

Using the digits of the number 1999, you need to make as many consecutive numbers as possible. In this case, you can:

• make numbers from numbers in the order in which they go in a given number, for example "19", "99", you can simply use a separate number
• keep order (i.e. unit ahead)
• use addition, subtraction, multiplication, division
• use square root
• enclose numbers in brackets
• raise a number to a power, and the power must consist of these figures, for example: 19 ^(9-9) = 1

Here is the seed for the first 7 numbers:

1. = 19-9-9
2. = 1 ⁹ +9: 9
3. = 1 * 9: 9 * sqrt (9)
4. = 1 + 9-9 + sqrt (9)
5. = 1 + 9: 9 + sqrt (9)
6. = 1 ⁹ * 9-sqrt (9)
7. = 19-9-sqrt (9)
8. = ...

Then, who wants to strain the brain, can try to reach hundreds. :)
')
UPD: One of the comments suggested using factorial, I remember such a thing, so I add to the condition:

• can use factorial

Since there was a small debate about the use of the "-" sign in front of the unit, and in the condition of a restriction on this was not, it is allowed to use a minus.

At the moment, the number 68 remains vacant.