$$ display $$ I_i (x-c_i) = \ sum_ {j = 1} ^ n a_ {ij} | x_j-c_ {ij} | ^ {p_ {ij}} + b_i, p_ {ij}> 0 $ $ display $$
$$ display $$ I (x) = min \ {\ sum_ {j = 1} ^ m a_ {ij} | x_j-c_ {ij} | ^ {p_ {ij}} + b_i, i = \ overline {1 , N} \} $$ display $$
$$ display $$ I_1 (x-c_1) = 7 | x_1 | ^ 2 + 7 | x_2 | ^ 2, $$ display $$
$$ display $$ I_2 (x-c_2) = 5 | x_1 + 2 | ^ {0.5} +5 | x_2 | ^ {0.5} +6, $$ display $$
$$ display $$ I_3 (x-c_3) = 5 | x_1 | ^ {1.3} +5 | x_2 + 2 | ^ {1.3} +5, $$ display $$
$$ display $$ I_4 (x-c_4) = 5 | x_1 | ^ {1} +5 | x_2-4 | ^ {1} +8, $$ display $$
$$ display $$ I_5 (x-c_5) = 4 | x_1-2 | ^ {1.5} +4 | x_2-2 | ^ {1.5} +7, $$ display $$
$$ display $$ I_6 (x-c_6) = 5 | x_1-4 | ^ {1.8} +5 | x_2 | ^ {1.8} +9, $$ display $$
$$ display $$ I_7 (x-c_7) = 6 | x_1-4 | ^ {0.6} +6 | x_2-4 | ^ {0.6} +4, $$ display $$
$$ display $$ I_8 (x-c_8) = 6 | x_1 + 4 | ^ {0.6} +6 | x_2-4 | ^ {1.6} +3, $$ display $$
$$ display $$ I_9 (x-c_9) = 3 | x_1 + 4 | ^ {1.2} +3 | x_2 + 4 | ^ {0.5} +7.5, $$ display $$
$$ display $$ I_ {10} (x-c_ {10}) = 2 | x_1-3 | ^ {0.9} +4 | x_2 + 5 | ^ {0.3} +8.5, $$ display $$
$$ display $$ I (x) = min \ {I_i (x-c_i), i = \ overline {1, N} \}. $$ display $$
def get_test_function_method_min(n: int, a: List[List[float]], c: List[List[float]], p: List[List[float]], b: List[float]): """ :param n: :param a: , , / :param c: :param p: :param b: :return: , , """ def func(x): l = [] for i in range(n): res = 0 for j in range(len(x)): res = res + a[i][j] * np.abs(x[j] - c[i][j]) ** p[i][j] res = res + b[i] l.append(res) res = np.array(l) return np.min(res) return func
$$ display $$ I_ {Y, i} (x-c_i) = - \ frac {1} {b_i * \ sum_ {j = 1} ^ m a_ {ij} | x_j-c {ij} | ^ {p_ {ij}} + d_i}, b_i> 0, d_i> 0 $$ display $$
$$ display $$ I (x) = \ sum_ {i = 1} ^ N I_ {Y, i} (x-c_i) $$ display $$
$$ display $$ I_1 (x-c_1) = - \ frac {1} {| x_1 + 4 | ^ 1 + | x_2 | ^ 1 + 0.25}, $$ display $$
$$ display $$ I_2 (x-c_2) = - \ frac {1} {2 | x_1 | ^ 1 + 2 | x_2 | ^ 1 + 0.2}, $$ display $$
$$ display $$ I_3 (x-c_3) = - \ frac {1} {0.5 | x_1 + 3 | ^ {0.6} +0.5 | x_2-3 | ^ {0.6} +0.1}, $$ display $$
$$ display $$ I_4 (x-c_4) = - \ frac {1} {1.5 | x_1-2 | ^ 1 + 1.5 | x_2-2 | ^ 1 + 0.3}, $$ display $$
$$ display $$ I_5 (x-c_5) = - \ frac {1} {0.8 | x_1 + 3 | ^ 1 + 0.8 | x_2 + 4 | ^ 1 + 0.35}, $$ display $$
$$ display $$ I (x_1, x_2) = \ sum_ {i = 1} ^ 5 I_ {Y, i} (x-c_i) $$ display $$
def get_tf_hyperbolic_potential_abs(n: int, a: List[float], c: List[List[float]], p: List[List[float]], b: List[float]): """ :param n: :param a: , :param c: :param p: :param b: , """ def func(x): value = 0 for i in range(n): res = 0 for j in range(len(x)): res = res + np.abs(x[j] - c[i][j]) ** p[i][j] res = a[i] * res + b[i] res = -(1 / res) value = value + res return value return func
$$ display $$ I_ {E, i} (x-c_i) = - d_i * exp \ {-b_i * sum_ {j = 1} ^ m a_ {ij} | x_j-c_ {ij} | ^ {p_ {ij}} \}, b_i> 0, d_i> 0 $$ display $$
$$ display $$ I (x) = \ sum_ {i = 1} ^ N I_ {E, i} (x-c_i) $$ display $$
$$ display $$ I_ {U, 1} (x-c_1) = - 6 * exp \ {- 1 * [| x_1 + 4 | ^ {0.3} + | x_2 | ^ 1] \}, $$ display $ $
$$ display $$ I_ {E, 2} (x-c_2) = - 5 * exp \ {- 2 * [| x_1 | ^ {1} + | x_2 | ^ 1] \}, $$ display $$
$$ display $$ I_ {E, 3} (x-c_3) = - 7 * exp \ {- 0.5 * [| x_1 + 3 | ^ {0.6} + | x_2-3 | ^ {1.1}] \}, $$ display $$
$$ display $$ I_ {E, 4} (x-c_4) = - 4 * exp \ {- 1.5 * [| x_1-2 | ^ {1.3} + | x_2-2 | ^ {0.8}] \}, $$ display $$
$$ display $$ I_ {U, 5} (x-c_5) = - 4.5 * exp \ {- 0.8 * [| x_1 + 3 | ^ {1.5} + | x_2 + 4 | ^ 2] \}, $$ display $$
$$ display $$ I (x_1, x_2) = \ sum_ {i = 1} ^ 5 I_ {E, i} (x-c_i) $$ display $$
def get_tf_exponential_potential(n: int, a: List[float], c: List[List[float]], p: List[List[float]], b: List[float]): """ :param n: :param a: , :param c: :param p: :param b: """ def func(x): value = 0 for i in range(n): res = 0 for j in range(len(x)): res = res + np.abs(x[j] - c[i][j]) ** p[i][j] res = (-b[i]) * np.exp((-a[i]) * res) value = value + res return value return func
Source: https://habr.com/ru/post/349660/
All Articles