International competition on obfuscation C code

IOCCC is back! The famous contest for the most convoluted code is designed to “check compilers for stress, demonstrate the subtleties of the C programming language and the importance of observing the programming style (doing the opposite).”

Under the conditions, ready-made programs of less than 4096 bytes in size can participate in the competition, with the number of significant characters (excluding spaces, tabs and signs); (), must not exceed 2048. On December 1, the application form for participation in the competition will be posted here .

The international competition for the most confusing code has been held annually since 1984, but since 2006, the event has been organized for the first time.

In 2004, the winner of the contest was a graphics multitasking OS, about 3.5 KB in size , with keyboard, mouse support, a primitive window subsystem, file system support and the ability to run ELF programs.
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Lovers of the unusual code will have something to look at: for example, here is the code of the flight simulator , which in the editor looks like a plane (the winner of the 1988 competition).

#include <math.h> #include <sys/time.h> #include <X11/Xlib.h> #include <X11/keysym.h> double L ,o ,P ,_=dt,T,Z,D=1,d, s[999],E,h= 8,I, J,K,w[999],M,m,O ,n[999],j=33e-3,i= 1E3,r,t, u,v ,W,S= 74.5,l=221,X=7.26, a,B,A=32.2,c, F,H; int N,q, C, y,p,U; Window z; char f[52] ; GC k; main(){ Display*e= XOpenDisplay( 0); z=RootWindow(e,0); for (XSetForeground(e,k=XCreateGC (e,z,0,0),BlackPixel(e,0)) ; scanf("%lf%lf%lf",y +n,w+y, y+s)+1; y ++); XSelectInput(e,z= XCreateSimpleWindow(e,z,0,0,400,400, 0,0,WhitePixel(e,0) ),KeyPressMask); for(XMapWindow(e,z); ; T=sin(O)){ struct timeval G={ 0,dt*1e6} ; K= cos(j); N=1e4; M+= H*_; Z=D*K; F+=_*P; r=E*K; W=cos( O); m=K*W; H=K*T; O+=D*_*F/ K+d/K*E*_; B= sin(j); a=B*T*DE*W; XClearWindow(e,z); t=T*E+ D*B*W; j+=d*_*D-_*F*E; P=W*E*BT*D; for (o+=(I=D*W+E *T*B,E*d/K *B+v+B/K*F*D)*_; p<y; ){ T=p[s]+i; E=cp[w]; D=n[p]-L; K=D*mB*TH*E; if(p [n]+w[ p]+p[s ]== 0|K <fabs(W=T*rI*E +D*P) |fabs(D=t *D+Z *Ta *E)> K)N=1e4; else{ q=W/K *4E2+2e2; C= 2E2+4e2/ K *D; N-1E4&& XDrawLine(e ,z,k,N ,U,q,C); N=q; U=C; } ++p; } L+=_* (X*t +P*M+m*l); T=X*X+ l*l+M *M; XDrawString(e,z,k ,20,380,f,17); D=v/l*15; i+=(B *lM*r -X*Z)*_; for(; XPending(e); u *=CS!=N){ XEvent z; XNextEvent(e ,&z); ++*((N=XLookupKeysym (&z.xkey,0))-IT? N-LT? UP-N?& E:& J:& u: &h); --*( DN -N? N-DT ?N== RT?&u: & W:&h:&J ); } m=15*F/l; c+=(I=M/ l,l*H +I*M+a*X)*_; H =A*r+v*XF*l+( E=.1+X*4.9/l,t =T*m/32-I*T/24 )/S; K=F*M+( h* 1e4/l-(T+ E*5*T*E)/3e2 )/SX*dB*A; a=2.63 /l*d; X+=( d*lT/S *(.19*E +a *.64+J/1e3 )-M* v +A* Z)*_; l += K *_; W=d; sprintf(f, "%5d %3d" "%7d",p =l /1.7,(C=9E3+ O*57.3)%0550,(int)i); d+=T*(.45-14/l* Xa*130-J* .14)*_/125e2+F*_*v; P=(T*(47 *Im* 52+E*94 *Dt*.38+u*.21*E) /1e2+W* 179*v)/2312; select(p=0,0,0,0,&G); v-=( W*FT*(.63*mI*.086+m*E*19-D*25-.11*u )/107e2)*_; D=cos(o); E=sin(o); } } 

Here is another example.

Program for calculating the number of pi by analyzing its own area ( 1988 )

 #define _ -F<00||--F-OO--; int F=00,OO=00;main(){F_OO();printf("%1.3f\n",4.*-F/OO/OO);}F_OO() { _-_-_-_ _-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_-_-_-_-_ _-_-_-_-_-_-_-_ _-_-_-_ }