Learning to count
Habra
Today is Friday, the blog is closed, so you can relax a bit.
When I read Habra, some posts are very deeply deposited inside the head. So deep that sometimes you forget about their existence at all until the event linking them comes.
')
It would seem that there is a connection between these posts:
Uncompromising replacement for a 60-watt light bulb
Chrome 9: Breakthrough in speed, support for 3D and web applications
Can HTML5 and Flash get along?
I agree, the connection between the two lower ones is, of course, direct. But with the first post somehow at first glance, not very. Especially with my title. And she is.
I opened the post number 1, and there the author failed to insert a YouTube video, so he gave a link that opened a video about a light bulb. Chrome was deployed in full ekan, so that the video was shown in the resolution of approximately 1920x950. And in the head, somewhere deep inside, sits post number 2. Because of this, it became very interesting how the video is played. It turned out through the flash. And even deeper in the head is sitting post number 3. I decided to measure the consumption of processor resources - 32%. And here in the middle of the video show three llamas with numbers: 60 W, 15 W and <10 W. And I think about 32% of the processor load. I decided to check where in numbers between these three lamps there will be a flash, playing through a 18 ”laptop 720p video.
I think.
Battery capacity declared by the manufacturer: 4800 mA / h.
The manufacturer promises 2 hours of battery life. It would be enough for him to make the daggers, with a capacity of 2400 mA / h for two hours of battery life.
Further, the battery produces a current of about 20 V. From the course of high school physics or Wikipedia, we know / learn that V = W / A. And this W is the same W that is shown in the video about light bulbs.
If you add the prefix m to the letter A, then you need to add it to W (division, elementary school) - add: V = mW / mA. V we have, mA we also have, we calculate mW. To do this, multiply both sides of the equation by mA: V * mA = mW. Let's substitute the numbers: 2400 * 20 = 48000.
48000 mW = 48W.
How many watts eats flash, if the picture played by them occupies 88% of the screen, and the execution of its code makes the processor work at 32% power?
Friday math tells me that 48W * 0.32% * 0.88 = 13.5W.
This means that for energy efficiency, the flash is located between the energy-saving light bulb and the LED light bulb.
PS: maybe the manufacturer has deceived me and it makes sense to move the post to protect the rights of consumers?
Today is Friday, the blog is closed, so you can relax a bit.
When I read Habra, some posts are very deeply deposited inside the head. So deep that sometimes you forget about their existence at all until the event linking them comes.
')
It would seem that there is a connection between these posts:
Uncompromising replacement for a 60-watt light bulb
Chrome 9: Breakthrough in speed, support for 3D and web applications
Can HTML5 and Flash get along?
I agree, the connection between the two lower ones is, of course, direct. But with the first post somehow at first glance, not very. Especially with my title. And she is.
I opened the post number 1, and there the author failed to insert a YouTube video, so he gave a link that opened a video about a light bulb. Chrome was deployed in full ekan, so that the video was shown in the resolution of approximately 1920x950. And in the head, somewhere deep inside, sits post number 2. Because of this, it became very interesting how the video is played. It turned out through the flash. And even deeper in the head is sitting post number 3. I decided to measure the consumption of processor resources - 32%. And here in the middle of the video show three llamas with numbers: 60 W, 15 W and <10 W. And I think about 32% of the processor load. I decided to check where in numbers between these three lamps there will be a flash, playing through a 18 ”laptop 720p video.
I think.
Battery capacity declared by the manufacturer: 4800 mA / h.
The manufacturer promises 2 hours of battery life. It would be enough for him to make the daggers, with a capacity of 2400 mA / h for two hours of battery life.
Further, the battery produces a current of about 20 V. From the course of high school physics or Wikipedia, we know / learn that V = W / A. And this W is the same W that is shown in the video about light bulbs.
If you add the prefix m to the letter A, then you need to add it to W (division, elementary school) - add: V = mW / mA. V we have, mA we also have, we calculate mW. To do this, multiply both sides of the equation by mA: V * mA = mW. Let's substitute the numbers: 2400 * 20 = 48000.
48000 mW = 48W.
How many watts eats flash, if the picture played by them occupies 88% of the screen, and the execution of its code makes the processor work at 32% power?
Friday math tells me that 48W * 0.32% * 0.88 = 13.5W.
This means that for energy efficiency, the flash is located between the energy-saving light bulb and the LED light bulb.
PS: maybe the manufacturer has deceived me and it makes sense to move the post to protect the rights of consumers?
Source: https://habr.com/ru/post/113183/
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